Question

37 задание, заранее спасибо

Answer 1

$\displaystyle\tt {} \ \ \ 10101\cdot\bigg(\frac{5}{111111}+ \frac{5}{222222}-\frac{4}{3\cdot7\cdot11\cdot13\cdot37}\bigg)=\\\\\\ =10101\cdot \bigg(\frac{5}{3\cdot7\cdot11\cdot13\cdot37}+ \frac{5}{2\cdot3\cdot7\cdot11\cdot13\cdot37}-\frac{4}{3\cdot7\cdot11\cdot13\cdot37}\bigg)=\\\\\\ =3\cdot7\cdot13\cdot37\cdot\frac{5\cdot2+5-4\cdot2}{2\cdot3\cdot7\cdot11\cdot13\cdot37}=\frac{10+5-8}{2\cdot11}=\frac{7}{22}$