Question

Укажите число корней в уравнении: х^2-8х+17=1. Назовите их

Answer 1

$x {}^{2} - 8x + 16 = 0 \\ d = 8 {}^{2} - 4 \times ( - 16) = 128 \\ x = - ( - 8) + - \sqrt{128} \\ x1 = 8 + 8 \sqrt{2} = 4 + 4 \sqrt{2} \\ x2 = 8 - 8 \sqrt{2} = 4 - 4 \sqrt{2}$

Answer 2

${x}^{2} - 8x + 17 = 1 \\ {x}^{2} - 8x + 16 = 0 \\ {(x - 4)}^{2} = 0 \\ x - 4 = 0 \\ x = 4$