Question

Номер три ответь буду рад много балов

Answer 1

$1)\frac{c^{3} }{c^{2}-8c+16 }-\frac{c^{2} }{c-4}=\frac{c^{3} }{(c-4)^{2} }-\frac{c^{2} }{c-4} =\frac{c^{3}-c^{3}+4c^{2}}{(c-4)^{2} }=\frac{4c^{2} }{(c-4)^{2}}\\\\2)\frac{c^{2} }{c^{2}-16 }-\frac{c}{c-4}=\frac{c^{2} }{(c-4)(c+4)}-\frac{c}{c+4}=\frac{c^{2}-c^{2} -4c }{(c-4)(c+4)} =\frac{-4c}{(c-4)(c+4)}\\\\3)\frac{4c^{2} }{(c-4)^{2} } :\frac{-4c}{(c-4)(c+4)}=\frac{4c^{2} }{(c-4)^{2} }*\frac{(c-4)(c+4)}{-4c}=-\frac{c(c+4)}{c-4} =\frac{c^{2} +4c}{4-c}$

Тождество доказано

Answer 2

1. c³/(c²-8c+18)=c³/(c-4)².

2. c³/(c-4)²-c²/(c-4)=(c³-c²*(c-4))/(c-4)=(c³-c³+4c²)/(c-4)²=4c²/(c-4)².

3. c²/(c²-16)-c/(c-4)=c²/((c-4)(c+4))-c/(c-4)=(c²-c*(c+4))/(c²-16)=

=(c²-c²-4)/(c²-16)=-4c/(c²-16).

4. (4c²/(c-4)²):(-4c/(c²-16))=4c²*(c-4)*(c+4)/(-4c*(c-4)²)=-c*(c+4)/(c-4)=

=c*(c+4)/(4-c)=(c²+4c)/(4-c).