Question

(1-cos2a+sin2a)/(1+cos2a+sin2a)

Answer 1

$\frac{1-Cos2\alpha+Sin2 \alpha} {1+Cos2\alpha+Sin2\alpha} = \frac{2Sin^{2}\alpha+2Sin\alpha Cos\alpha}{2Cos^{2}\alpha+2Sin\alpha Cos \alpha} }= \frac{2Sin\alpha(Sin\alpha+Cos\alpha)}{2Cos\alpha(Cos\alpha+Sin\alpha)}= \frac{Sin\alpha} {Cos\alpha}=tg \alpha$