Question

Упростить
1).
(x*!y+z)*(!x+y)+!z

Answer 1

$\displaystile (x*\overline y+z)(\overline x+y)+\overline z=0+0+\overline xz+yz+\overline z=z(\overline x+y)+\overline z=\\\overline x+y+\overline z$