Question

решите показательное уравнение:

Answer 1

Ответ на фото/////////////

Answer 2

$64 {}^{x} + 2 {}^{2 + 3x} - 12 = 0 \\ \\ ( {2}^{6} ) {}^{x} + {2}^{2} \times 2 {}^{3x} - 12 = 0 \\ \\ {2}^{6x} + 4 \times 2 {}^{3x} - 12 = 0 \\ \\ (2 {}^{3x} ) {}^{2} + 4 \times 2 {}^{3x } - 12 = 0 \\ \\ {t}^{2} + 4t - 12 = 0 \\ \\ t = 2 \\ t = - 6 \\ \\ {2}^{3x} = 2 \\ {2}^{3x} = - 6 \\ \\ \\ x = \frac{1}{3}$