Question

(5x-8)^2≥(8x-5)^2 пожалуйста

Answer 1

Ответ:

x ∈ [-1 ; 1]

Объяснение:

|5x - 8| - |8x-5| ≥ 0

1) 5x - 8 - (8x-5) ≥ 0, при 5x-8 ≥ 0 и 8x-5 ≥ 0

2) -(5x - 8) - (8x-5) ≥ 0, при 5x-8 < 0 и 8x-5 ≥ 0

3) 5x - 8 - (-(8x-5)) ≥ 0, при 5x-8 ≥ 0 и 8x-5 < 0

4) -(5x - 8) - (-(8x-5)) ≥ 0, при 5x-8 < 0 и 8x-5 < 0

1) x ≤ -1, x ≥ $\frac{8}{5}$, x ≥ $\frac{5}{8}$

2) x ≤ -1, x < $\frac{8}{5}$, x ≥ $\frac{5}{8}$

3) x ≤ -1, x ≥ $\frac{8}{5}$, x < $\frac{5}{8}$

4) x ≤ -1, x < $\frac{8}{5}$, x < $\frac{5}{8}$

1) x ∈ ∅

2) x ∈ [$\frac{5}{8}$ ; 1]

3) x ∈ ∅

4) x ∉ [-1 ; $\frac{5}{8}$)

x ∈ [-1 ; 1]