Question

ученикам 8 класса ВОПРОС

Answer 1

3x/(x-3)+(x+5)54/((6-2x)(5x+x^2))=3x/(x-3)+54(x+5)/(2(3-x)x(5+x))=3x/(x-3)+27/(x(3-x))=(3x^2-27)/(x(x-3))=3(x^2-9)/(x(x-3))=3(x-3)(x+3)/(x(x-3))=3(x+3)/x при х≠{-5; 3}
Ответ: 3(x+3)/x при х≠{-5; 3}

Answer 2

$\frac{3x}{x-3}+ \frac{x+5}{6-2x}* \frac{54}{5x+x^{2}} =\frac{3x}{x-3} +\frac{x+5}{2(3-x)} *\frac{54}{x(5+x)} =\frac{3x}{x-3} +\frac{27}{x(3-x)} =\frac{3x}{x-3} -\frac{27}{x(x-3)} =\frac{3x^{2}-27}{x(x-3)} =\frac{3(x^{2}-9)}{x(x-3)} =\frac{3(x-3)(x+3)}{x(x-3)} =\frac{3x+9}{x}$