Question

log3 32/log3 2 + log7 27/log7 3

Answer 1

$\frac{log_3 32}{log_3 2 } +\frac{log_7 27}{log_7 3 } = \frac{log_3 2^5}{log_3 2 } +\frac{log_7 3^3}{log_7 3 }=\frac{5*log_3 2}{log_3 2 } +\frac{3*log_7 3}{log_7 3 }=5+3=8$