Question

помогите решить г) и д)

Answer 1

$y = (2x^5 + 4x^{-3} - 3)^4 \\ y' = 4(2x^5 + 4x^{-3} - 3)^3 (10x^4 - 12x^{-4})$

$y = \frac{cos(5x)}{sin(4x)} \\ y' = \frac{-5sin(5x)sin(4x) - 4cos(4x)cos(5x)}{sin^2(4x)}$