Question

ПОМОГИТЕ!!!

найдите разность дробей

Answer 1

$\frac{f-4}{f+3}- \frac{f}{f-3}= \frac{f^{2}-3f-4f+12-f^{2}-3f}{(f-3)(f+3)}= \frac{12-10f}{f^{2}-9}$

Answer 2

( (f-4)(f-3) - f(f+3) ) / (f+3)(f-3) = ( f^2-7f+12 - f^2 - 3f) / (f+3)(f-3)=

= (-10f+12)/(f^2-9)