Question

Помогите пж!!! по алгебре

Answer 1

$1)0,(14)=\frac{\frac{14}{100}} {1-\frac{1}{100}}= \frac{14}{100}: \frac{99}{100}= \frac{14}{99}\\2)0,12(7)=0,12+\frac{\frac{7}{1000}} {1-\frac{1}{10}}=0,12+ \frac{7}{900}= \frac{12}{100}+ \frac{7}{900}= \frac{108+7}{900}= \frac{115}{900}= \frac{23}{180}$