Question

Помогите пожалуйста!!!!!!!!!!!!!!!!!!

Answer 1

$\frac{18p^4}{y^6}\frac{y^7}{24p^8}=\frac{3y}{4p^4}$

$\frac{9y^2-1}{y^2-4}:\frac{6y-2}{y-2}=\frac{(3y-1)(3y+1)}{(y-2)(y+2)}*\frac{y-2}{2(3y-1)}=\frac{3y+1}{2y+4};$