Question

6а^2+19а-1
__________
1-25а^2

Answer 1

(6a²+19a-1)/(1-25a²)=(a+3,22)(6a-0,3)/(1-5a)(1+5a)

1-25a²=(1-5a)(1+5a)

6a²+19a-1=6(a-(-3,22))(a-0,05)=(a+3,22)(6a-0,3)

D=(-19)²-4×6×(-1)=361+24=385
a1=(-19-√385)/2×6=(-19-19,6)/12=-38,6/12=-3,218~-3,22
a2=(-19+√385)/2×6=(-19+19,6)/12=0,6/12=0,05