Question

ПОМОГИТЕ СРОЧНО 2 ЗАДАНИЕ!!!!!!!!!!

Answer 1

$\frac{y^2-4z^2}{3z+6}*\frac{z^2+4z+4}{5y+10z}=\frac{(y-2z)(y+2z)}{3(z+2)}*\frac{(z+2)^2}{5(y+2z)}=\frac{(y-2z)}{3}*\frac{(z+2)}{5}=\frac{yz+2y-2z^2-4z}{15}$