Question

Log3(1-6x)=log3(17-x2)

Answer 1

$log_{3}(1 - 6x) = log_{3}(17 - {x}^{2} ) \\ 1 - 6x = 17 - {x}^{2} \\ {x }^{2} - 6x - 16 = 0 \\ (x - 8)(x + 2) = 0 \\ x1 = 8 \\ x2 = - 2$
ОДЗ
$\\ \left \{ {{1 - 6x > 0} \atop {17 - x ^{2} > 0}} \right.$
ОДЗ удовлетворяет лишь
$x = - 2$
Ответ
$x = - 2$