Question

сократить дробь. Помогите пжжж

Answer 1

$2x^2-x-15=0\; ,\; \; D=121\; ,\; \; x_1=\frac{1-11}{4}=-\frac{5}{2}\; ,\; x_2=\frac{1+11}{4}=3\\\\x^2-6x+9=0\; ,\; \; (x-3)^2=0\; ,\; \; x=3\\\\\\\frac{2x^2-x-15}{x^2-6x+9}=\frac{2(x+\frac{5}{2})(x-3)}{(x-3)^2}=\frac{(2x+5)(x-3)}{(x-3)^2}=\frac{2x+5}{x-3}\\\\\\\star \; \; ax^2+bx+c=a(x-x_1)(x-x_2)\; \; \star$