Question

ребят как решить второй и третий?

Answer 1

$(\frac{n^{-4}}{4m^{-5}})^{-2}*6n^6m^2= (\frac{4m^{-5}}{n^{-4}})^{2}*6n^6m^2= \frac{4^2m^{-5*2}}{n^{-4*2}}*6n^6m^2= \frac{16m^{-10}}{n^{-8}}*6n^6m^2= \frac{16n^{8}}{m^{10}}*6n^6m^2= 16*6n^{8+6}m^{2-10}=96n^{14}m^{-8}=\frac{96n^{14}}{m^{8}}$

$\frac{5^0*25^{-7}}{125^{-6}*5^1}= \frac{5^0*(5^2)^{-7}}{(5^3)^{-6}*5^1}= \frac{5^0*5^{-14}}{5^{-18}*5^1}= \frac{5^{0-14}}{5^{-18+1}}= \frac{5^{-14}}{5^{-17}}=5^{-14-(-17)}=5^{-14+17} =5^3=125$