Question

-16ab + 8(a+b)^2 при a=√2 b=√5

Answer 1

-16аb + 8 (a^2+2ab+b^2)

-8(2ab-(a^2+2ab+b^2))

-8(2ab-a^2-2ab-b^2)

-8(-a^2-b^2)

-8(-2-5)

-8×(-7)

ОТВЕТ 56