Question

x^2/2(x-5)+25/2(5-x)
срочно!!!

Answer 1

$x\neq 5$

$\frac{x^2}{2(x-5)}+\frac{25}{2(5-x)}=\frac{x^2}{2(x-5)}-\frac{25}{2(x-5)}=\frac{x^2-25}{2(x-5)}=\frac{(x-5)(x+5)}{2(x-5)}=\frac{x+5}{2}$

Answer 2

$\frac{ {x}^{2} }{2(x - 5)} + \frac{25}{2(5 - x)} = \frac{ {x }^{2} - 25}{2(x - 5)} = \frac{(x - 5)(x + 5)}{2(x - 5)} = \frac{x + 5}{2}$