Question

sin2a+sin4a/cos2a-cos4a=g Найти sin2a

Answer 1

$frac{sin2a+sin4a}{cos2a-cos4a}=g\ frac{2sin3a*cosa}{2sin3a*sina}=g\ ctga=g\ a=arcctg(g)\ sin2a=sin(2arcctg(g))\ arcctg(g)=x\ sin2x=frac{2ctgx}{1+ctg^2x}=frac{2ctg(arcctg(g))}{1+(ctg(arcctg(g)))}=frac{2g}{1+g^2}$