Question

Помогите пожалуйста , номер 41 (ж , з , и ) 50 баллов

Answer 1

$\displaystyle \frac{x^3-x}{x-x^2}=\frac{x(x^2-1)}{x(1-x)}=\frac{x(x-1)(x+1)}{x(1-x)} =-(x+1)=-x-1\\ \\ \\ \frac{a^2x-ax^2}{x^2-ax}=\frac{ax(a-x)}{x(x-a)}=-a\\ \\ \\ \frac{p^2-2pn+n^2}{n^2-pn}=\frac{(p-n)^2}{n(n-p)}=\frac{n-p}{n}$

Answer 2

ж
$\frac{{x}^{3} - x}{x - {x}^{2} } = \frac{x( {x}^{2} - 1) }{ - x(x - 1)} = \\ = - \frac{x(x - 1)(x + 1)}{x(x - 1)} = \\ = - (x + 1) = - x - 1$
з
$\frac{ {a}^{2}x - a {x}^{2} }{ {x}^{2} - ax } = \frac{ax(a - x)}{ - x(- x + a)} = - a$
и
$\frac{ {p}^{2} - 2pn + {n}^{2} }{ {n}^{2} - pn } = \frac{ {n}^{2} - 2pn + {p}^{2} }{ {n}^{2} - pn } = \\ = \frac{(n - p) ^{2} }{ n( n - p)} = \frac{( n - p)}{n}$