Question

$2^{x^{2} -3x+8} =64$

Answer 1

${2}^{ {x}^{2} - 3x + 8 } = 64 \\ {2}^{ {x}^{2} - 3x + 8} = {2}^{6} \\ {x}^{2} - 3x + 8 = 6 \\ {x}^{2} - 3x + 2 = 0 \\ d = {b}^{2} - 4ac = 9 - 4 \times 2 = 1 \\ x1 = \frac{3 + 1}{2} = \frac{4}{2} = 2 \\ x2 = \frac{3 - 1}{2} = \frac{2}{2} = 1$
Ответ: 1; 2.

Answer 2

I hope this helps you