Question

Помогие с примером...
>~<

Answer 1

$\displaystyle \frac{a^2-16a+64}{64-8a}=\frac{(a-8)^2}{8(8-a)}=-\frac{a-8}{8}$

Если а = -0.4, то $-\dfrac{a-8}{8} =-\dfrac{-0.4-8}{8} =1.05$

Answer 2

$\frac{ {a}^{2} - 16a + 64 }{64 - 8a} = \frac{ {(8 - a)}^{2} }{8(8 - a)} = \frac{8 - a}{8}$
при а = -0,4:
$\frac{8 - ( - 0.4)}{8} = \frac{8.4}{8} = \frac{2.1}{2} = 1.05$