Question

помогите пожалуйста решить уравнения:

(x-2)(x+2)=x^2-2(x-5)

(x-4)(x+4)=x^2+4(x+1)

(x-3)(x+3)=x^2-3(x-6)

Answer 1

$(x - 2)(x + 2) = {x}^{2} - 2(x - 5) \\ {x}^{2} - 4 = {x}^{2} - 2x + 10 \\ {x}^{2} - {x}^{2} - 4 + 2x - 10 = 0 \\ 2x - 14 = 0 \\ 2x = 14 \\ x = 7$
Ответ: 7.

$(x - 4)(x + 4) = {x}^{2} + 4(x + 1) \\ {x}^{2} - 16 = {x}^{2} + 4x + 4 \\ {x}^{2} - 16 - {x}^{2} - 4x - 4 = 0 \\ - 4x - 20 = 0 \\ - 4x = 20 \\ x = - 5$
Ответ: -5.

$(x - 3)(x + 3) = {x}^{2} - 3(x - 6) \\ {x}^{2} - 9 = {x}^{2} - 3x + 18 \\ {x}^{2} - 9 - {x}^{2} + 3x - 18 = 0 \\ 3x - 27 = 0 \\ 3x = 27 \\ x = 9$
Ответ: 9