Question

Выполнить умножение:
(x-8)(4+2x)
Преоброзуйте в многочлен:
(x+2)^2-14x

Answer 1

$(x - 8)(4 + 2x) = x \times 4 - 8 \times 4 + x \times 2x - 8 \times 2x = 4x - 32 + 2 {x}^{2} - 16x = 2 {x}^{2} - 12x - 32$
${(x + 2)}^{2} - 14x = {x}^{2} + 2 \times x \times 2 + {2}^{2} - 14x = {x}^{2} + 4x + 4 - 14x = {x}^{2} - 10x + 4$

Answer 2

1)(х-8)(4+2х)=4х+3х-32-16х=7х-16х-32=-9х-32.
2)(х+2)'2-14х=х'2+4х+4-14х=х'2-10х+4.