Question

Помогите плиз,срочно(((
№6
Под буквой
Ж),и),к)
№7
Под буквой
б),в),г).

Answer 1

6.
ж)
${a}^{4} - a {b}^{3} = a( {a}^{3} - {b}^{3} ) = a(a - b)( {a}^{2} + ab + {b}^{2} )$
и)
${x}^{10} - x {y}^{3} = x( {x}^{9} - {y}^{3} ) = x( {x}^{3} - y)( {x}^{6} + {x}^{3} y + {y}^{2} )$
к)
${m}^{13} n + m {n}^{13} = mn( {m}^{12} + {n}^{12} ) = mn( {m}^{4} + {n}^{4} )( {m}^{8} + {m}^{4} {n}^{4} + {n}^{8} )$
7.
б)
$(a - 3b)(a + 3b)( {a}^{4} + 9 {a}^{2} {b}^{2} + 81 {b}^{4} ) = ( {a}^{2} - 9 {b}^{2} )( {a}^{4} + 9 {a}^{2} {b}^{2} + 81 {b}^{4} ) = {a}^{6} - 729 {b}^{6}$
в)
${(2x + 1)}^{2} {(4 {x}^{2} - 2x + 1)}^{2} = {((2x + 1)(4 {x}^{2} - 2x + 1)) }^{2} = {(8 {x}^{3} + 1)}^{2} = 64 {x}^{6} + 16 {x}^{3} + 1$
г)
${(3 + x)}^{2} {(9 - 3x + {x}^{2}) }^{2} = {((3 + x)(9 - 3x + {x}^{2}) }^{2} = {(27 + {x}^{3}) }^{2} = 729 + 54 {x}^{3} + {x}^{6}$