Предмет: Математика, автор: kolyambasik

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Ответы

Автор ответа: snow99
1

(x - 3)(x  - 4)(x - 5) = (x - 2)(x - 4)(x - 5) \\ (x - 3)(x - 4)(x - 5)  - (x - 2)(x - 4)(x - 5) = 0 \\ (x - 4)(x - 5)(x - 3 - (x - 2)) = 0 \\ (x - 4)(x - 5)(x - 3 - x + 2) = 0 \\ (x - 4)(x - 5) \times ( - 1) = 0 \\  (x - 4)(x -5) = 0 \\ x  = 4 \\ x = 5
Ответ: 4; 5.

 \frac{4}{x - 9}  +  \frac{9}{x - 4}  = 2 \\  \frac{4(x - 4) + 9(x - 9) }{(x - 9)(x - 4)}  =  \frac{2(x - 9)(x  - 4)}{(x - 9)(x - 4)}  \\  \frac{4x - 16 + 9x - 81 - 2(x - 9)(x - 4)}{(x - 9)(x - 4)}  = 0 \\  \frac{13x - 97 - 2( {x}^{2} - 9x - 4x + 36) }{(x - 9)(x - 4)}  = 0 \\  \frac{13x - 97 - 2 {x}^{2}  + 18x + 8x - 72}{(x - 9)(x - 4)}  = 0 \\  \frac{ - 2 {x}^{2}  +  39x - 169}{(x - 9)(x - 4)}  = 0 \\ 2 {x}^{2}  - 39x + 169 = 0 \\ d =  {b}^{2}  - 4ac = 1521 - 4 \times 2 \times 39 = 169 \\ x1 =  \frac{39 + 13}{2 \times 2} =  \frac{52}{4}  = 13 \\ x2 =  \frac{39 - 13}{2 \times 2}  =  \frac{26}{4}  =  \frac{13}{2}
Ответ: 13/2; 13.
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