Question

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Answer 1

$10^{2+\frac{1}{2}lg75-2lg(2\sqrt[4]{3})}$

$10^{2+lg\sqrt{75}-2lg\sqrt[4]{48}}$

$10^{2+lg\sqrt{75}-lg\sqrt{48}}$

$10^{lg100+lg\sqrt{\frac{75}{48}}} =10^{lg100+lg1.25}$

$10^{lg125}=125$

Ответ: 125