Question

Помогите с алгеброй пожалуйста (x/2y)^3 * x^2-y^2/x^3 : x^2-2xy+y^2/x^2

Answer 1

${( \frac{x}{2y}) }^{3} \times \frac{ {x}^{2} - {y}^{2} }{ {x}^{3} } \div \frac{ {x}^{2} - 2xy + {y}^{2} }{ {x}^{2} } = \frac{ {x}^{3} }{ 8{y}^{3} } \times \frac{(x - y)(x + y)}{ {x}^{3} } \div \frac{ {(x - y)}^{2} }{ {x}^{2} } = \frac{(x - y)(x + y)}{8 {y}^{3} } \times \frac{ {x}^{2} }{ {(x - y)}^{2} } = \frac{ {x}^{2} (x + y)}{8 {y}^{3}(x - 2) }$