Question

решите пожалуйста эти 2 номера
если надо помогу с историей 9-11 класс

Answer 1

132.а)
${ (\frac{2a}{ {m}^{2} c} )}^{3} \div { (\frac{4 {a}^{2} }{3m {c}^{2} } )}^{2} = \frac{ 8 {a}^{3} }{ {m}^{6} {c}^{3} } \div \frac{16 {a}^{4} }{9 {m}^{2} {c}^{4} } = \frac{8 {a}^{3} }{ {m}^{6} {c}^{3} } \times \frac{9 {m}^{2} {c}^{4} }{16 {a}^{4} } = \frac{1 \times 9c}{ {m}^{4} \times 2a} = \frac{9c}{2 {m}^{4} a}$
б)
${( \frac{ - a}{9 {c}^{2} x})}^{3} \div { (\frac{2a}{3c {x}^{2} } )}^{4} = \frac{ - {a}^{3} }{729 {c}^{6} {x}^{3} } \div \frac{16 {a}^{4} }{81 {c}^{4} {x}^{8} } = \frac{ - {a}^{3} }{729 {c}^{6} {x}^{3} } \times \frac{81 {c}^{4} {x}^{8} }{16 { a }^{4} } = \frac{ - 1 \times {x}^{5} }{9 {c}^{2} \times 16a } = - \frac{ {x}^{5} }{144a {c}^{2} }$
133.а)
$\frac{8mn}{9a {x}^{2} } \div ( \frac{6m}{5x} \div \frac{3 {x}^{2} }{2n} ) = \frac{8mn}{9a {x}^{2} } \div ( \frac{6m}{5x} \times \frac{2n}{3 {x}^{2} } ) = \frac{8mn}{9a {x}^{2} } \div \frac{4mn}{5 {x}^{3} } = \frac{8mn}{9 a{x}^{2} } \times \frac{5 {x}^{3} }{4mn} = \frac{2 \times 5x}{9a} = \frac{10x}{9a}$
б)
$( \frac{0.5ax}{2m} \div \frac{x}{4 {m}^{2} } ) \div \frac{m}{a} = ( \frac{0.5ax}{2m} \times \frac{4 {m}^{2} }{x} ) \times \frac{a}{m} = \frac{am}{1} \times \frac{a}{m} = {a}^{2}$