Question

Вычислите интеграл: $\int\limits^4_3 {\sqrt{x-3}} \, dx$

Answer 1

int ot 3 do 4 sqrt(x - 3) d(x - 3) = (x - 3)^3/2 : 3/2 |ot 3 do 4 = 2/3 * (x - 3)^3/2 | ot 3 do 4 = 2/3 *(1/2 - 0) = 2/3 * 1/2 = 1/3