Question

Помогите пожалуйста решить в2,в3,в4.

Answer 1

B2.
$\frac{ {x}^{2} {y}^{3} }{xy} = {x}^{2 - 1} {y}^{3 - 1} = x {y}^{2}$
При х = -3, y = 5:
$x {y}^{2} = - 3 \times {5}^{2} = - 3 \times 25 = - 75$
B3.
$3(x - 1) = 2(x - 1) \\ 3x - 3 = 2x - 2 \\ 3x - 2x = - 2 + 3 \\ x = 1$

B4.
$3(x - 1) \leqslant 2(x - 1) \\ 3x - 3 \leqslant 2x - 2 \\ 3x - 2x \leqslant - 2 + 3 \\ x \leqslant 1$
x ∈ (-∞; 1].

Answer 2

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