Question

(66)решите неравенство...

Answer 1

$f(x)=2x^3+12x^2\\ f'(x)=6x^2+24x\\ \\ g(x)=9x^2+72x\\ g'(x)=18x+72\\ \\ 6x^2+24x+18x+72<0\\ x^2+7x+12<0\\ D=49-48=1\\ x=\dfrac{-7\pm1}{2} \ \Rightarrow \ x\in (-4;\ -3)$

Ответ: ∅