Question

выполните действия : а)
$(1 + 2 \sqrt{3)} (1 - 2 \sqrt{3} )$
б)
$(2 \sqrt{3} - \sqrt{2} )(3 \sqrt{2} + 2 \sqrt{3} )$
в)
$(3 - \sqrt{3} )(2 - \sqrt{3} )$
г)
$( \sqrt{5} + \sqrt{8} )( \sqrt{5 + 3 \sqrt{2} } )$
д)
$5 \sqrt{2 } - \sqrt{125} )( \sqrt{125} - \sqrt{2} ) - 250$

Answer 1

a) 1-4*3=1-12=-11

b)6√6+4*3-3*2-2√6 = 4√6+12-6=6+4√6

c)6-3√3-2√3+3 = 9-5√3

d) √(√5+√8)^2 *(5+3√2) = √(5+8+√40)*(5+3√2) = √(13+2√10)(5+3√2)=

=√(65+39√2+10√10+6√20) = √(65+39√2+10√10+12√5)

e) (5√2-5√5)(5√5-√2)-250 = 25√10-10-125+5√10-250 =

=30√10-385

Answer 2

$a) (1-2\sqrt{3})(1+2\sqrt{3})=1^2-(2\sqrt{3})^2=1-12=-11\\\\ b)(2\sqrt{3}-\sqrt{2})(3\sqrt{2}+2\sqrt{3})=6\sqrt{6}-6+12-2\sqrt{6}=6+4\sqrt{6}\\\\ c)(3-\sqrt{3})(2-\sqrt{3})=6-2\sqrt{3} -3\sqrt{3} +3 =9-5\sqrt{3}\\\\ d)(\sqrt{5}+2\sqrt{2})\sqrt{5+3\sqrt{2}} = \sqrt{25+3\sqrt{10}} +\sqrt{10\sqrt{2}+12} \\\\ e)(5\sqrt{2} -5\sqrt{5} )(5\sqrt{5} -\sqrt{2})-250=25\sqrt{10} -125-10+5\sqrt{10}-250=\\=30\sqrt{10} -385$