Question

Помогите плиз очень срочно !!

Answer 1

3

$16\leq 2^{x+3}$

$2^4\leq 2^{x+3}$

$4\leq x+3$

$x\geq 1$

4

$5^{7x+3}-\frac{1}{5}\geq 0\\\\ 5^{7x+3}\geq \frac{1}{5}$

$5^{7x+3}\geq 5^{-1}\\ \\ 7x+3\geq -1\\ \\ x\geq- \frac{4}{7}$