Question

Найдите значение производной функции f(x)=4cos(2x+п/3) при х=п/3

Answer 1

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Answer 2

f'(x)=(4cos(2x+π/3))'=
4•(-sin(2x+π/3))•(2x+π/3)'=
-8•sin(2x+π/3)
f'(π/3)=-8sin(2π/3+π/3)=-8sinπ=0