Question

Упростить: $\frac{3}{\sqrt{6} - \sqrt{3}} + \frac{4}{ \sqrt{7} + \sqrt{3} }$

Answer 1

Вроде так.

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Answer 2

$\sqrt{6}+ \sqrt{3} + \frac{4}{ \sqrt{7} + \sqrt{3} } = \sqrt{6}+ \sqrt{3} + \frac{4(\sqrt{7} - \sqrt{3})}{ (\sqrt{7} + \sqrt{3})(\sqrt{7} - \sqrt{3}) } =\\ = \sqrt{6}+ \sqrt{3} + \frac{4(\sqrt{7} - \sqrt{3})}{ 4 } =\sqrt{6}+ \sqrt{3} + \sqrt{7} - \sqrt{3}= \sqrt{6} + \sqrt{7}.$