Question

как из
$( \frac{1}{x} + \frac{1}{x - 2}) \times \frac{4}{3} = 1$
зделать
$4(2x - 2) = 3( {x}^{2} ) - 2x$

Answer 1

$( \frac{1}{x} + \frac{1}{x-2} )* \frac{4}{3} =1 \\ \\ ( \frac{1}{x} + \frac{1}{x-2} )=1: \frac{4}{3} \\ \\ ( \frac{1}{x} + \frac{1}{x-2} )= \frac{3}{4} \\ \\ \frac{x-2+x}{x(x-2)} = \frac{3}{4} \\ \\ \frac{2x-2}{x^2-2x} = \frac{3}{4} \\ \\ 4(2x-2)=3(x^2-2x)$