Question

Найдите область определения:
$y = \sqrt{18 + 3x - {x}^{2} } - \frac{5}{x - 4}$

Answer 1

$x \neq 4 \\ 18+3x-x^2 \ \textgreater \ = 0 \\ D = 9 +72 = 81 = 9^2 x_1 = -2( -3+9) = -3 x_2 = -2( -3-9) = 6 \\ \\ \\ x \geq -3, \ \ \ x \leq 6,\ \ \ x \neq 4$