Предмет: Химия, автор: Аноним

980 г 5% раствора серной кислоты нейтрализует раствор гидроксида калия Какая масса получинной соли

Ответы

Автор ответа: mrvladimir2

Дано:
m(p-pa H2SO4) = 980 г
ω(H2SO4) = 5% = 0.05
Найти:
m(K2SO4) - ?

Решение.
M(H2SO4) = 98 г/моль
m(H2SO4) = 980 г* 0.05 = 49 г
n(H2SO4) = 49 г/98 г/моль = 0,5 моль
M(K2SO4) = 174 г/моль

2KOH + H2SO4 = K2SO4 + 2H2O

Из УХР n(K2SO4)=n(H2SO4)=0.5 моль
m(K2SO4) = 0,5 моль*174 г/моль = 87 г
Ответ: 87 г

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