Question

Помогите алгебра 8 класс срочно ,3 упрастите выражение

Answer 1

$....=( \frac{6}{(y-3)(y+3)}- \frac{1}{y-3})* \frac{(y+3)(y+3)}{5} = \frac{6-y-3}{(y-3)(y+3)} * \frac{(y+3)(y+3)}{5} = \\ \\ \frac{(3-y)(y+3)}{5(y-3)} =- \frac{(y-3)(y+3)}{5(y-3)} = -\frac{y+3}{5}$