Question

Найдите производные функций.

Answer 1

$y'=(x^4)'=4x^3\\\\y'=4'=0\\\\y'=(-\frac{3}{x})'=- \frac{-3}{x^2}= \frac{3}{x^2}\\\\y'=(3x+2)'=3\\\\y'=(2cosx-4 \sqrt{x})'=-2sinx-4\cdot \frac{1}{2\sqrt{x}} =-2sinx- \frac{2}{\sqrt{x}}$