Question

Система : 16-x²≥0
x-2>0

Answer 1

$\left \{ {{16-x^2 \geq 0} \atop {x-2 \geq 0}} \right. \\\\ \left \{ {{x^2-4^2 \leq 0} \atop {x \geq 2}} \right. \\\\ \left \{ {{(x+4)(x-4) \leq 0} \atop {x \geq 2}} \right. \\\\ \left \{ {{x-4 \leq 0} \atop {x \geq 2}} \right. \\\\ \left \{ {{x \leq 4} \atop {x \geq 2}} \right. \\\\ 2 \leq x \leq 4\\\\ x\in[2;\ 4]$