Question

все решения неравенства

Answer 1

$\sqrt{x^2} =|x| \\ x^2=|x|^2$
$|x|^2+|x|- \frac{1}{8} \ \textless \ 0 \\ \frac{-8-\sqrt{96}}{16} \ \textless \ |x|\ \textless \ \frac{-8+\sqrt{96}}{16} \\ \frac{-2-\sqrt{6}}{4} \ \textless \ |x|\ \textless \ \frac{-2+\sqrt{6}}{4} \\ \frac{2-\sqrt{6}}{4} \ \textless \ x\ \textless \ \frac{-2+\sqrt{6}}{4}$