Question

Оч нужно................!!!!!

Answer 1

$a_1 = \frac{2*1 + 1}{(3 + (-1)^1)^1} = \frac{3}{2} \\\\ a_2= \frac{2*2 + 1}{(3 + (-1)^2)^2} = \frac{5}{16} \\\\ a_3= \frac{2*3+1}{(3+(-1)^3)^3} = \frac{7}{8} \\\\ a_{n+1}= \frac{2(n+1)+1}{(3+(-1)^{n+1})^{n+1}} = \frac{2n+3}{(3+(-1)^{n+1})^{n+1}}$