Question

найдите координаты точек пересечения прямой 5x-7y＝12 с осями координат.

Answer 1

$y = \frac{5x - 12}{7} \\ y = 0 \\ \frac{5x - 12}{7} = 0 \\ 5x - 12 = 0 \\ 5x = 12 \\ x = 2.4 \\ \\ x = 0 \\ y = \frac{5 \times 0 - 12}{7} \\ y = \frac{ - 12}{7} = - 1 \frac{5}{7}$

Answer 2

\begin{lgathered}y = \frac{5x - 12}{7} \\ y = 0 \\ \frac{5x - 12}{7} = 0 \\ 5x - 12 = 0 \\ 5x = 12 \\ x = 2.4 \\ \\ x = 0 \\ y = \frac{5 \times 0 - 12}{7} \\ y = \frac{ - 12}{7} = - 1 \frac{5}{7}\end{lgathered}​y=​7​​5x−12​​​y=0​​7​​5x−12​​=0​5x−12=0​5x=12​x=2.4​​x=0​y=​7​​5×0−12​​​y=​7​​−12​​=−1​7​​5​​​​