Предмет: Математика,
автор: antezinka
Решите пожалуйста
Номер 236
а) 201²-199²=(201-199)(201+199)=...
б)105²-95²=...
в) 25,6²-4,4²=..
Номер 235
Разложите на множители.
а) а²b²-4c²=(ab)²-(2c)²=...
б) 16-9x⁴=4²-(3x²)²=...
в) x²-y²z⁴=...
г) z⁴-1=...
Ответы
Автор ответа:
0
1) (201-199)(201+199)=2*400=800
ayaulym19:
2) (105-95)(105+95)=10*200=2000
Автор ответа:
1
236.
а)![201^{2} -199^{2}=(201-199)(201+199)=2*400=800 201^{2} -199^{2}=(201-199)(201+199)=2*400=800](https://tex.z-dn.net/?f=+201%5E%7B2%7D+-199%5E%7B2%7D%3D%28201-199%29%28201%2B199%29%3D2%2A400%3D800)
б)![105^{2} - 95^{2} =(105-95)(105+95)=10*200=2000 105^{2} - 95^{2} =(105-95)(105+95)=10*200=2000](https://tex.z-dn.net/?f=105%5E%7B2%7D+-+95%5E%7B2%7D+%3D%28105-95%29%28105%2B95%29%3D10%2A200%3D2000)
в)![25.6^{2} - 4.4^{2} =(25.6-4.4)(25.6+4.4)=21.2*30=212*3=636 25.6^{2} - 4.4^{2} =(25.6-4.4)(25.6+4.4)=21.2*30=212*3=636](https://tex.z-dn.net/?f=+25.6%5E%7B2%7D+-+4.4%5E%7B2%7D+%3D%2825.6-4.4%29%2825.6%2B4.4%29%3D21.2%2A30%3D212%2A3%3D636)
235.
а)![a^{2} b^{2} -4c^{2} = (ab)^{2}-(2c)^{2}= (ab-2c)(ab+2c) a^{2} b^{2} -4c^{2} = (ab)^{2}-(2c)^{2}= (ab-2c)(ab+2c)](https://tex.z-dn.net/?f=+a%5E%7B2%7D++b%5E%7B2%7D+-4c%5E%7B2%7D+%3D++%28ab%29%5E%7B2%7D-%282c%29%5E%7B2%7D%3D+%28ab-2c%29%28ab%2B2c%29)
б)![16-9x^{4}=4^{2}-(3x^{2})^{2}=(4-3x^{2})(4+3x^{2}) 16-9x^{4}=4^{2}-(3x^{2})^{2}=(4-3x^{2})(4+3x^{2})](https://tex.z-dn.net/?f=16-9x%5E%7B4%7D%3D4%5E%7B2%7D-%283x%5E%7B2%7D%29%5E%7B2%7D%3D%284-3x%5E%7B2%7D%29%284%2B3x%5E%7B2%7D%29)
в)![x^{2} - y^{2} z^{4} = x^{2} -(yz^{2})^{2}=(x-yz^{2})(x+yz^{2}) x^{2} - y^{2} z^{4} = x^{2} -(yz^{2})^{2}=(x-yz^{2})(x+yz^{2})](https://tex.z-dn.net/?f=+x%5E%7B2%7D+-+y%5E%7B2%7D++z%5E%7B4%7D+%3D+x%5E%7B2%7D+-%28yz%5E%7B2%7D%29%5E%7B2%7D%3D%28x-yz%5E%7B2%7D%29%28x%2Byz%5E%7B2%7D%29)
г)
а)
б)
в)
235.
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в)
г)
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