Предмет: Алгебра, автор: roma435452220

Найдите угловой коэффициент касательной к графику функции f(x)=2cos x-1/2 tg x в точке с абсциссой x0=пи

Ответы

Автор ответа: краковягра
0
k=f'(π/4)
f'(x)=-2sinx - 4cos4x
f'(π/4)=-2sin(π/4)-4cos(4*π/4)=-2*√2/2 - 4*(-1)=-√2+4=4-√2≈2,6
roma435452220: это точно правельно
roma435452220: откуда пи/4 взялось
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