Question

Теңдеуді шешіңіз:2cos6x-√2=0

Answer 1

2cos6x-√2=0
2сos6x=√2
cos(6x)=√2/2
cos(2п-6x)=√2/2
6x=arccos(√2/2)
2п-6x=arccos(√2/2)
6x=п/4
2п-6x=п/4
6x=п/4+2kп
2п-6х=п/4+2kп
х=п/24+kп/3
x=7п/24-kп/3
x=п/24+kп/3
x=7п/25+kп/3
                        п/24+kп/3
x=(система)
                        7п/24+kп/3